<PRE><B>Question 720818</B>
Given F(x)=-2x^2+6x-1. Find the vertex and the axis of symmetry, and graph the function. 
So far I&#39;ve graphed the function. I think the vertex is 3/2,7/2, but I&#39;m not sure. I need help finding the axis of symmetry please, thanks!
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Vertex occurs at x = -b/(2a) = -6/(2*-2) = 3/2
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f(3/2) = -2(3/2)^2+6(3/2)-1 = 7/2
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So, you are correct.
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Since the parabola opens downward the the vertex is at x = 3/2
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Axis of symmetry is x = 3/2
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Cheers,
Stan H.
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