Question 8006
First, find the slope of the line that connects the two points given. 
Then, write the general equation of a line with that slope.
Last, calculate the y-intercept of the line.

Some useful equations for doing this work:
The {{{slope = (y[2]-y[1])/(x[2]-x[1])}}}

The slope-intercept equation of a line is {{{y = mx + b}}} where m is the slope.
The y-intercept is the value of y when {{{x = 0}}}. 
Try doing the work before looking at my work below:
{{{slope = (-5 -(-3))/(3-1)=(-5+3)/(3-1)=-2/2=-1}}}
{{{y = -x + b}}}
{{{-1=(-5-y)/(3-x)=(-5-y)/(3-0)=(-5-y)/3}}} putting in the point (0, y)
{{{-1=(-5-y)/3}}} to calculate the y-intercept
{{{-3 = -5-y}}} [multiplying both sides by 3
{{{2 = -y}}} [adding 5 to both sides]
{{{y = -2}}} [multiplying both sides by -1 and rearranging]
So the equation is 
{{{y = -x - 2}}}