Question 712487
(2+5/4x-1)= (-2/(4x-1)^2)
I started it already but i do not really understand. This is what I have done:
(2/1+5/4x-1)=(-2/(4x-1)^2)
2(4x-1)^2+5(4x-1)=-2
I do not know what else to do
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{{{2(4x-1)^2+5(4x-1)=-2}}}
{{{2(16x^2 - 8x + 1) + 20x - 5 = -2}}}
{{{32x^2 - 16x + 2 + 20x - 5 = -2}}}
{{{32x^2 + 4x - 1 = 0}}}
*[invoke solve_quadratic_equation 32,4,-1]
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You can check both, see if they work in the original equation.