Question 709299
Solve
a) x^3-x^2-4x+4=0
b) x^3-4x^2+x+6=0
c) x^3-x^2-3x+6=0
d) x^4-3x^3-2x^2+12x-8=0

Can you please help me with a detailed explanation and show me how to do it?
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a) x^3-x^2-4x+4=0
Try the factors of 4, plus and minus.
1, 2 & 4
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Sub 1 for x:
1 - 1 - 4 + 4 = 0
+ 1 is a zero --> (x-1) is a factor.
Divide by x-1, then factor what's left, if possible.