Question 702114
area of a triangle is: {{{A=b*h/2}}}



if given: {{{b= 2ft}}} and {{{A= 28ft^2}}}}

 {{{A=b*h/2}}}....plug in given values

{{{28ft^2=(2ft*h)/2}}}

{{{28ft^2=(cross(2)ft*h)/cross(2)}}}

{{{28ft^2=1ft*h}}}

{{{28ft^2/1ft=h}}}

{{{28ft^cross(2)/1cross(ft)=h}}}

{{{highlight(28ft=h)}}}


if given: {{{h=22.6yd}}} and  {{{A= 282.5yd^2}}}

 {{{A=b*h/2}}}....plug in given values

 {{{282.5yd^2=(b*22.6yd)/2}}}

{{{282.5yd^2=(b*cross(22.6)11.3yd)/cross(2)}}}

{{{282.5yd^2=b*11.3yd}}}

{{{282.5yd^2/11.3yd=b}}}

{{{25(yd^cross(2)/cross(yd))=b}}}

{{{highlight(25yd=b)}}}