Question 700443
Solve 2^x=5^x^2 for x 
------
2^x = 5^(x^2)
---
Take the log of both sides:
x*log(2) = x^2(log(5))
-----
0.6990x^2 - 0.3010x = 0
---
x[0.6990x - 0.3010] = 0
---
x = 0 or x = (0.3010/0.6990)
---
x = 0 or x = 0.431
================
Cheers,
Stan H.
---------------

a)0.431
b)2.322
c)0 and 0.431
d)0 and 2.322