<PRE><B>Question 696223</B>
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Square the measure of each of the three sides.  You will have one number that is larger than the other two.  Add the two smaller numbers.  If the sum is equal to the large number, the triangle is right.  Otherwise not.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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