Question 693238
Write in standard form.It is a Hyperbola. The vertices are (0,+-1) and the foci are (0, +-5).
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This is a hyperbola with horizontal transverse axis.
Its standard form of equation: {{{(y-k)^2/a^2-(x-h)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center
For given hyperbola:
center:(0,0)
a=1 (distance from center to vertices on transverse axis)
a^2=1
c=5 (distance from center to foci on transverse axis)
c^2=25
c^2=a^2+b^2
b^2=c^2-a^2=25-1=24
Equation of given hyperbola:{{{y^2-x^2/24=1}}}