<PRE><B>Question 687083</B>
Membership in an elite oraganization requires a test score in the upper 30% range. If the mean is 115 and the standard deviation is 12,find the lowest acceptable score that would enable a candidate to apply for membership. Assume the variable is normally distributed.
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Find the z-score with a left-tail 0 70%.
invNorm(0.70) = 0.5244
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Find the corresponding test score using x = z*s + u
x = 0.5244*12 + 115 = 121.29
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Cheers,
Stan H.
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