<PRE><B>Question 687042</B>
membership in an elite organization requires a test score in the upper 30% range. if the mean is 115 and the standard deviation is 12, find the lowest acceptable score that would enable a candidate to apply for membership. assume the variable is normally distributed.
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Use the form x = z*s+u
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Find the z-value with a left-tail of 0.70
invNorm(0.70) = 0.5244
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x = 0.5244*12 + 115 
x = 121.29
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Cheers,
Stan H.</PRE>