Question 61124
Write the equation of the line with slope -1/2  and y-intercept (0, 3).  Then graph the line.
The slope intercept form of a line is {{{highlight(y=mx+b)}}}, m=slope, (0,b)=y-intercept.
For this problem, m=-1/2 and (0,b)=(0,3)
{{{highlight(y=(-1/2)x+3)}}}
You plot the y-intercept by putting a point on 3 on the y axis.
From that point you use your slope to plot another point.  {{{highlight(Slope=m=rise/run)}}}.  Our slope is m=-1/2, go down 1 (keep the sign with the rise, go up when it's positeve and down when it's negative) and right 2 (always run right) and plot another point at what should be (2,2).
Connect your points and you should have a line that looks tike this:
{{{graph(300,200,-10,10,-10,10,(-1/2)x+3)}}}
Happy Calculating!!!