Question 674227
Find the equation of the line with the given properties. Express.the equation in general form or slope intercept form 
perpendicular to the line -3x+y=-21 containing points (6,-4)
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-3x+y=-21
y = 3x - 21
Slope = 3
The slope of lines perpendicular is the negative inverse, = -1/3
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Use y = mx + b and the point to find b, the y-intercept
-4 = (-1/3)*6 + b
b = -2
--> y = (-1/3)x - 2
Or y = -x/3 - 2 (better format)
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x + 3y = -6 (standard format)