Question 672647
If four consecutive odd integers had a sum of 96, what would be the largest integer?
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The hard way:
n + n+2 + n+4 + n+6 = 96
4n+12 = 96
n = 21
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Better way:
96/4 = 24, the center.
2 below & 2 above
--> 21, 23, 25 & 27