Question 670035
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Hi,
A firm will promote two employees out of a group of six men and three women.
process of random selection...demonstrates that the probability of randomly selecting 2 women...
is less than the probability of randomly selecting 2 men or 1 of each.  
P(2 women) = {{{3C2*6C0/ (9C2)= 3/(9C2) }}}
P(2 men) = {{{3C0*6C2/(9C2)=15/(9C2) }}}
P(1 each) = {{{3C1*6C1/(9C2)= 18/(9C2)}}}