Question 657894
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Hi,
triangle with vertices A(3,8) B(7,2) and C(0,1), find the length of the median drawn to the side BC
Midpoint of BC: Midpoint  Pt(x,y):  ( {{{(x[1] + x[2])/2}}}, {{{(y[1] + y[2])/2  )}}})
B(7,2) and 
C(0,1) Midpoint (3.5,1.5)
the length of the median:
Distance:  D = {{{sqrt ((x[1]-x[2])^2+(y[1]-y[2])^2))}}}
(3.5,1.5)
(3,8)      D = {{{sqrt((.5)^2 + (-6.5)^2)}}}