Question 59599
log 3125 to the base 5
3125 = 5*5*5*5*5
     = 5^5
log 3125 to the base 5= log5^5 to the base 5
==>                   5 log 5 to the base 5 [log a^b = b loga]
                     = 5*1 [loga to base a is always 1]
                     = 5

so log5(3125) = 5

Good Luck!!!