Question 651642
The ones and hundreds digits of a three-digit number are interchanged and the
 new number is subtracted from the first number.
 The difference obtained is three-digit number 59x. Find x. 
:
The equation should be:
(100x + 10y + z) - (100z + 10y + x) = 590 + x
Remove the brackets and combine like terms
100x - x + 10y - 10y - 100z + z = 590 + x
99x - 99z = 590 + x
we know that the right side also has to be divisible by 99, (99*6=594)
x = 4