Question 650129
{{{ ( 7.6*10^(-2) * .0076*10^(-3) ) / ( 1.2*10^(-10) ) }}}
You only need 2 rules:
{{{ a^b * a^c = a^( b+c) }}}
and
{{{ 1 / a^b = a^(-b) }}}
And, what amounts to the same thing,
{{{ 1 / a^(-b) = a^b }}}
---------------------
Simplify a little
{{{ ( 7.6*10^(-2) * 7.6*10^(-3)*10^(-3) ) / ( 1.2*10^(-10) ) }}}
{{{ ( 7.6^2 * 10^( -2-3-3 ) ) / ( 1.2*10^(-10) ) }}}
{{{ 57.76 * 10^( -8 ) *( 1/1.2) * 10^10 }}}
{{{ ( 5776/120 ) * 10^( 10 - 8 ) }}}
{{{ ( 5776/120 ) * 10^2 }}}
{{{ 57760/12 }}}
{{{ 14440/3 }}}
Hope I got it