Question 643911
1.{{{x+y=9.0}}}
2.{{{0.50x+.20y=3.75}}}
From eq. 1,
{{{y=9-x}}}
Use this in eq. 2,
{{{0.50x+0.2(9-x)=3.75}}}
{{{0.50x+1.8-0.2x=3.75}}}
{{{0.30x+1.8=3.75}}}
{{{0.30x= 1.95}}}
{{{x=1.95/0.30}}}
{{{highlight(x=6.5)}}}
Now use the substitution again,
{{{y=9-x}}}
{{{y=9-6.5}}}
{{{highlight(y=2.5)}}}