Question 637773
{{{y/z= 192 /12}}}.........->.......{{{y=(192/12)z}}}}

if {{{y}}}varies directly as {{{z}}}, we have:

{{{y = kz}}}...first find {{{k}}}...->....{{{k=192/12}}}->......{{{k=16}}}

Now that we have the value of {{{k}}}, we can plug in the new value, and solve for the new value of {{{y}}}

if {{{z= 17}}}

{{{y = 16*17}}}

{{{y=272}}}