Question 636872
3x^2-12/x^2-6x-16 X x^2+x+1/3x^2+6x+3 
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[3(x^2-4)]/[(x-8)(x+2)] * [(x^2+x+1)/(3(x^+2x+1)]
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= [(x-2)/(x-8)] * [(x^2+x+1)/(x^2+2x+1)]
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Cheers,
Stan H.
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