Question 636466

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,-4\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=-4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,-2\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=-2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-2--4)/(3--3)}}} Plug in {{{y[2]=-2}}}, {{{y[1]=-4}}}, {{{x[2]=3}}}, and {{{x[1]=-3}}}



{{{m=(2)/(3--3)}}} Subtract {{{-4}}} from {{{-2}}} to get {{{2}}}



{{{m=(2)/(6)}}} Subtract {{{-3}}} from {{{3}}} to get {{{6}}}



{{{m=1/3}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,-4\right)] and *[Tex \LARGE \left(3,-2\right)] is {{{m=1/3}}}