Question 7205
{{{5/(x+2) - 3x/(x^2-3x)}}}
{{{5/(x+2) - 3x/(x(x-3))}}}
{{{5/(x+2) - 3/(x-3)}}} --> now i am going to multiply both parts of the fraction by 1, so they don't actually change, but my "1" will be written as fractions. I am doing this so that both fraction end up with the same denominator, so then i can subtract them... just like fractions with just numbers...


{{{(5/(x+2))*((x-3)/(x-3)) - (3/(x-3))*((x+2)/(x+2))}}}

{{{(5(x-3)/((x+2)(x-3))) - (3(x+2)/((x-3)(x+2)))}}}
{{{(5(x-3)- 3(x+2))/((x+2)(x-3)) }}}


so now we get {{{(5x-15-3x-6)/((x+2)(x-3)) }}}

{{{(2x-21)/((x+2)(x-3)) }}}


jon.