Question 633792
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Hi,

Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept.
line.
Through: (-3,-3), perpendicular to y= -3x
New perpendicular Line  m = 1/3  (negative reciprocal of -3)
 y = (1/3)x + b   |Using ordered pair (x,y):(-3-3)  to solve for b
-3 = (1/3)*(-3) + b
-2 = b
 y = (1/3)x -2