Question 632182
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(0,0\right)]. So this means that {{{x[1]=0}}} and {{{y[1]=0}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-11,-10\right)].  So this means that {{{x[2]=-11}}} and {{{y[2]=-10}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-10-0)/(-11-0)}}} Plug in {{{y[2]=-10}}}, {{{y[1]=0}}}, {{{x[2]=-11}}}, and {{{x[1]=0}}}



{{{m=(-10)/(-11-0)}}} Subtract {{{0}}} from {{{-10}}} to get {{{-10}}}



{{{m=(-10)/(-11)}}} Subtract {{{0}}} from {{{-11}}} to get {{{-11}}}



{{{m=10/11}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(0,0\right)] and *[Tex \LARGE \left(-11,-10\right)] is {{{m=10/11}}}


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