Question 626907
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The difference between any two consecutive odd numbers is 2.


The *[tex \LARGE n]th odd number is *[tex \LARGE 2n\ -\ 1], and the next odd number after that is *[tex \LARGE 2n\ +\ 1].  Then *[tex \LARGE (2n\ +\ 1)\ -\ (2n\ -\ 1)\ =\ 2]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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