Question 57654
how do you write the equation of a line that contains (-4,10)and is parallel to y=2/7x+3?
Parallel lines have the same slope.  
The equation that they gave you is in slope intercept form:{{{highlight(y=mx+b)}}}, where m=slope, and (0,b)=y-intercept.
The slope of the line parallel to y=2/3x+3 is:
{{{y=highlight(2/7)x=3}}} slope=m=2/7
When you have a point and a slope you can make the equation of the line using the point-slope formula:{{{highlight(y-y1=m(x-x1))}}}, where m=slope, and (x1,y1)=given point.
m=2/7, x1=-4, and y1=10
{{{y-10=(2/7)(x-(-4))}}}
{{{y-10=(2/7)(x+4)}}}
{{{7(y-10)=7(2/7)(x+4)}}}
{{{7y-70=2(x+4)}}}
{{{7y-70=2x+8}}}
{{{7y-70+70=2x+8+70}}}
{{{7y=2x+78}}}
{{{7y/7=2x/7+78/7}}}
{{{y=(2/7)x+78/7}}} <---slope intercept form of a line.
Happy Calculating!!!