Question 624889
(x^2+y^4)(x^2-y^4)


x^2(x^2-y^4)+y^4(x^2-y^4)


x^4-x^2y^4+x^2y^4-y^8


x^4-y^8


So (x^2+y^4)(x^2-y^4) = <font color="red">x^4-y^8</font>



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