Question 623957
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Let *[tex \LARGE x] represent the number of >$200 orders and *[tex \LARGE y] represent the number of $50-$200 orders.  We are given that the <$50 orders number *[tex \LARGE 2x\ + 12].  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ +\ 2x\ +\ 12\ =\ 384]


Which simplifies to


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ y\ =\ 372]


The cost equation is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8x\ +\ 6y\ +\ 4(2x\ +\ 12)\ =\ 2160]


Which simplifies to:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16x\ +\ 6y\ =\ 2112]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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