Question 623038
If {{{(x+1)/x}}} = 4
x + 1 = 4x
1 = 4x -x
1 = 3x
x = {{{1/3}}}
:
 find {{{(x^4+1)/(x^4)}}} = {{{((1/3)^4+1)/(1/3)^4)}}} = {{{(.0123456789+1)/.0123456789}}} = {{{(1.0123456789)/.0123456789}}} = 82