Question 622900
two taps can fill a tank in 15 and 12 minutes respectively.
a third tap can empty it in 20 minutes.
if all the taps are opened at the same time then in how much time will the tank be filled?
:
Let t = time required when all three taps are open.
Let the completed job = 1; (a full tank)
:
A typical shared work equation.
:
Fill + Fill - Empty = a full tank
{{{t/15}}} + {{{t/12}}} - {{{t/20}}} = 1
multiply by 60 to clear the denominators, results
4t + 5t - 3t = 60
6t = 60
t = 60/6
t = 10 minutes with all taps open