Question 620170
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Find three consecutive integers{{{highlight(x)}}}, {{{highlight(x+1)}}},  {{{highlight(x+2)}}}         
in which four times the sum of the first two is the same as six times the third
   4[ x + (x+1)] = 6(x+2)***
     4(2x+1) = 6(x+2)
     8x + 4 = 6x + 12
           2x = 8
            x = 4  Integers are 4,5,6
 CHECKING our Answer***
      4(9) = 6(6) = 36