Question 619981
Let 
First integer = x+1
Second integer=x+2
Third integer = x+3


Three consecutive integers such that the sum of the first two integers minus the third integer is four. 

(x+1+x+2)-(x+3)=4
2x+3-x-3=4
x=4



First integer = x+1=4+1=5
Second integer=x+2=4+2=6
Third integer = x+3=4+3=7

Three consecutive integers are 5,6,7