Question 616237


{{{2(x-4)^2-8=0}}} Start with the given equation.



{{{2(x-4)^2=0+8}}}Add {{{8}}} to both sides.



{{{2(x-4)^2=8}}} Combine like terms.



{{{(x-4)^2=(8)/(2)}}} Divide both sides by {{{2}}}.



{{{(x-4)^2=4}}} Reduce.



{{{x-4=""+-sqrt(4)}}} Take the square root of both sides.



{{{x-4=sqrt(4)}}} or {{{x-4=-sqrt(4)}}} Break up the "plus/minus" to form two equations.



{{{x-4=2}}} or {{{x-4=-2}}}  Take the square root of {{{4}}} to get {{{2}}}.



{{{x=4+2}}} or {{{x=4-2}}} Add {{{4}}} to both sides.



{{{x=6}}} or {{{x=2}}} Combine like terms.



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Answer:



So the solutions are {{{x=6}}} or {{{x=2}}}.