<PRE><B>Question 614922</B>
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Let *[tex \LARGE x] be the first number and then *[tex \LARGE x\ +\ 1] is the next consecutive number.  Then if their product is 90:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(x\ +\ 1)\ =\ 90]


Put the quadratic into standard form, then solve for *[tex \LARGE x].  Discard the positive root since the problem asks you to find negative integers.   Then calculate *[tex \LARGE x\ +\ 1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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