Question 56862
Suppose f(x) = (2x+1)/(x-1) and g(x)= x+1/x-2

Now you have to check that f(g(x))= x  

Let's check this: 

f(g(x)) = (2*g(x)+1)/(g(x)-1) 


        = [2*(x+1/x-2) + 1]/(x+1/x-2 -1)

        = [2*(x+1/x-2)+(x-2/x-2]/[x+1/x-2)-(x-2/x-2)]


        = [(2x+2+x-2)/(x-2)] / [x+1-x+2/(x-2)]


        = 2x+2+x-x / x+1-x+2
  
        = x