Question 610888
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Parallel lines have equal slopes.  Determine the slope of your given line by inspection of the cooefficient on x.  Then given that the x-coordinate of the x-intercept is 4, the x-intercept is the point (4,0).

Now that you have a slope and a point, you can use the point-slope form of an equation of a straight line to write the desired equation.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]

where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given/calculated slope.

Note: It is an error to report an intercept as a number.  An intercept is an ordered pair.  The x-intercept is a point (a,0) where a is the x-coordinate of the x-intercept and the y-intercept is a point (0,b) where b is the y-coordinate of the y-intercept.

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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