Question 603785
let length = x in
width = y in
Perimeter
2(x+y) = 28
x+y = 14

Area
xy = 48
x= 48/y

substitute x 

x+y =14
48/y + y = 14

multiply equation by y

48+y^2=14y

y^2-14y+48=0

y^2-8y-6y+48=0
y(y-8)-6(y-8)=0
(y-8)(y-6)=0

y = 6 OR 8

the dimensions are 8 in by 6 in