Question 602213
There are (5 C 3)*(6 C 2) = 10*15 = 150 ways to have exactly 3 men on the committee.


There are (5 C 4)*(6 C 1) = 5*6 = 30 ways to have exactly 4 men on the committee.


and


There is (5 C 5)*(6 C 0) = 1*1 = 1 way to have exactly 5 men on the committee.



Add these results up: 150+30+1 = 181


So there are <font color="red">181</font> ways to form the committee if there must be at least 3 men on the committee.