Question 601182
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,56\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=56}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-7,-65\right)].  So this means that {{{x[2]=-7}}} and {{{y[2]=-65}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-65-56)/(-7--3)}}} Plug in {{{y[2]=-65}}}, {{{y[1]=56}}}, {{{x[2]=-7}}}, and {{{x[1]=-3}}}



{{{m=(-121)/(-7--3)}}} Subtract {{{56}}} from {{{-65}}} to get {{{-121}}}



{{{m=(-121)/(-4)}}} Subtract {{{-3}}} from {{{-7}}} to get {{{-4}}}



{{{m=121/4}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,56\right)] and *[Tex \LARGE \left(-7,-65\right)] is {{{m=121/4}}}