Question 599410
I want to solve the exponential equation 2^x^3 + 5 = 0, where x^3 is the exponent to 2, but I can't take the (ln) of a negative number.
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{{{2^(x^3) = -5}}}
That's right, you can't.
There is no exponent that will give a result of -5.
No solution.