Question 593048
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Since the LHS of both equations is simply *[tex \LARGE y], set the two RHSs equal to each other and solve the resulting single variable equation in *[tex \LARGE x].  Once you have a value for *[tex \LARGE x], substitute that value back into either original equation and calculate the value of *[tex \LARGE y].  The solution set will contain a single ordered pair.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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