Question 592432
Solve the equation. (Do not use mixed numbers in the answer.) 
ln(5x-6)+ln(x) = ln(e)
ln(5x-6)+ln(x) =1
ln[(5x-6)(x)]=1
e^1=5x^2-6x=e
5x^2-6x-e=0
solve by following quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=5, b=-6, c=-e