Question 591703


{{{36x^2-25}}} Start with the given expression.



{{{(6x)^2-25}}} Rewrite {{{36x^2}}} as {{{(6x)^2}}}.



{{{(6x)^2-(5)^2}}} Rewrite {{{25}}} as {{{(5)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=6x}}} and {{{B=5}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(6x)^2-(5)^2=(6x+5)(6x-5)}}} Plug in {{{A=6x}}} and {{{B=5}}}.



So this shows us that {{{36x^2-25}}} factors to {{{(6x+5)(6x-5)}}}.



In other words {{{36x^2-25=(6x+5)(6x-5)}}}.