Question 587906
If 1n x=6 and 1n y=2 then 1n (xsquared/y)=
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{{{ln(x^2/y) = ln(x^2) - ln(y) = 2ln(x) - ln(y)}}}
= 2*6 - 2 = 10
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It looks like you have 1n, not ln
It's ln (LN), for natural log