Question 576592
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Use the definition of the logarithm function


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = \log_b(x) \ \ \Rightarrow\ \ b^y = x]


and the fact that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln(x)\ =\ \log_e(x)]


to write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ e^{-1}\ =\ x\ -\ 4]


Solve for *[tex \LARGE x]:  Add 4 to both sides and recall that *[tex \LARGE a^{-n}\ =\ \frac{1}{a^n}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{1}{e}\ +\ 4]


Use your calculator for a numerical approximation if you need one.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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