Question 576300
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{x\ +\ 4}\ +\ 2\ =\ x]


Add *[tex \LARGE -2] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{x\ +\ 4}\ =\ x\ -\ 2]


Square both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 4\ =\ x^2\ -\ 4x\ +\ 4]


Collect like terms and put the quadratic into standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 5x\ =\ 0]


Solve the quadratic.  Check both roots.  Discard the extraneous and invalid root.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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