Question 54610
SEEING THE FORMULA FOR THIS TYPE OF PROBLEM IS DISTANCE=SPEED*TIME

D=S*T OR S=560/(T+1) & S=480/T THEN 560/(T+1)=480/T OR 560T=480T+480 OR

80T=480 OR T=480/80 OR T=6 HOURS THUS THE SPEED IS S=560/(6+1) OR S=560/7 OR

S=80 MPH & S=480/6 OR S=80 MPH FOR BOTH LEGS OF THE FLIGHT.THE FIRST LEG TAKING 7 HOURS & THE LAST LEG TAKING 6 HOURS FOR A TOTAL OF 13 HOURS FOR THE 1040 MILE FLIGHT OR 1040=80*13 OR 1040=1040