Question 572853
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In any triangle the sum of the measures of any two sides must be strictly greater than the measure of the third side.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10\ +\ 12\ =\ 22\ <\ 23]

Therefore, there is no triangle with sides that measure 10, 12, and 23.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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