Question 571945
You have a triangle with area 15, a side of length 6, and a side of length 12. Find the value of the angle between these two sides in radians. Assume theta< pi/2
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let x= angle theta
Area of triangle=1/2*base*h
base=12
h=6sinx
..
15=1/2*12*6*sinx
15=36sinx
sinx=15/36
Using calculator
x&#8776;0.43 radians